张兴康 发表于 2020-7-26 14:03:51

用sql计算ABCDE*4=EDCBA(这五个数字不重复)

--一个五位数字ABCDE*4=EDCBA,这五个数字不重复
with a as
(select level - 1 as x from dual connect by level <= 10)
select a.x * 10000 + b.x * 1000 + c.x * 100 + d.x * 10 + e.x as y
from a a, a b, a c, a d, a e
where a.x > 0
   and (a.x * 10000 + b.x * 1000 + c.x * 100 + d.x * 10 + e.x) * 4 =
       e.x * 10000 + d.x * 1000 + c.x * 100 + b.x * 10 + a.x
   and (a.x <> b.x)
   and (a.x <> c.x and b.x <> c.x)
   and (a.x <> d.x and b.x <> d.x and c.x <> d.x)
   and (a.x <> e.x and b.x <> e.x and c.x <> e.x and d.x <> e.x);


with t as
(select level-1 as n from dual connect by level <=10)
select * from t a,t b, t c,t d,t e
where to_number(a.n||b.n||c.n||d.n||e.n)*4= to_number(reverse(a.n||b.n||c.n||d.n||e.n)) and a.n<>0

陈晓龙 发表于 2020-7-26 15:38:31

又整这些高级东西了哦!

万望 发表于 2020-7-28 23:53:25

陈晓龙 发表于 2016-2-26 15:38
又整这些高级东西了哦!

我也是说,大牛{:2_28:}

张兴康 发表于 2020-7-28 09:41:03

万望 发表于 2016-2-28 23:53
我也是说,大牛

{:3_60:}

陈晓龙 发表于 2020-7-28 16:07:24

万望 发表于 2016-2-28 23:53
我也是说,大牛

这娃儿厉害吧!
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